Hydbridizations, bond (valence) angles and bond lengths are the three principal factors defining the 3D structure of organic compounds, as they control the size and overall shape of building blocks from which matter is made up. These factors are considered to be fundamental of all chemistry, and must have been given during the PrePharm chemistry courses. The chapter below is provided as an auxiliary material to be reviewed by the students outside of the normal lecture hours. The more in debths coverage can be found in any undergraduate texbook of organic chemistry.
The outer shell electronic structure of the atomic carbon is:
The C atom should, therefore, be capable of forming two bonds only using its
half-filled 2p orbitals, and the resulting valence angle (the planar angle
between the bonds formed) should be 90o.
In contrast, valency of carbon in most compounds is four, and the valence angle is 109o28'. To account for this behavior it is considered (and also proven by theoretical calculations) that in carbon bearing molecules there is a promotion of one 2s electron into 2p orbital with subsequent mixing of all four orbitals 2s, 2px, 2py and 2pz to give four half-filled identical orbitals termed sp3 hybrid orbitals. Each of these orbitals is then be able to make a single bond to another atom.
Since all four sp3 orbitals are identical(other than orientation), they are evenly distributed in space to give 109o 28' valence angle. Thus, for example the structure of methane(Figure on right) is a regular tetrahedron, with each hydrogen position equidistant from the central carbon atom and all hydrogen atoms equivalent.
The sp3 orbitals have their electronic density extending much
further from the central C atom giving rise to strong bonding interactions at
the beginning of the process of bond formation, and stronger bonds in
general, since most electron density is now localized between the two atoms
(e.g. C and H) engaged in bonding. The new orbitals exist only in molecularly
bonded atoms (i.e. not in atomic carbon). The bonds between atoms using
either two sp3 orbitals, or two s orbitals, or s-sp3
combination are termed
(sigma) bonds, and
are the strongest covalent bonds known. Saturated hydrocarbons in general
feature only
bonds.
However, in contrast to sp3 hybridized carbon atom, uniform spatial distribution of three sp2 orbitals gives planar geometry; i.e. all orbitals are positioned within a single plane and form 120o valence angle with each other.
Furthermore, the unused electron occupies the 2p orbital oriented along the axis perpendicular to the hybridization plane. This pattern is termed sp2 hybridization and gives rise to different bond length, strength and geometry than those of the sp3 hybridized molecules.
-bond (pi).
Due to a less efficient overlap than in the case of a
bond, the
-bonds are somewhat weaker
(lower bond energy). A common example of this type of bonding is an olefinic
(alkene) double bond. Note, that the carbon geometry is planar, and that due
to the edge-to edge overlap in the
-bond no
rotation about the double bond is allowed, as it would disrupt 2p-2p
orbital overlap. This factor has a profound restricting effect on the ability
of unsaturated molecules to rotate about the double bond.
orbitals with the analogous orbitals of adjacent atoms (e.g. sp hybridized
carbon). This will give rise to a triple bond consisting of a single
bond and two mutually orthogonal
-bonds. This situation is represented by
acetylenes. The geometrical consequence of the sp hybridization is the
linearity of the structure.
Nitrogen in its atomic ground state has the following electronic structure:
Analogously to carbon atom the nitrogen atom should be able to form bonds
with the valence angle of 90o (three such bonds). Orbital
hybridization gives instead four orbitals, one of which is filled (two
electrons) and does not participate in bonding (two 2p nonbonding electrons
frequently called a lone electon pair). The remaining three hybrid orbitals
form the normal
bonds, analogously to a
carbon atom. The geometry of ammonia is therefore similar to that of methane,
except it features a free electron pair. This electron pair determines
property of nitrogen in sp3 hybridized compounds as an electron
donation (Lewis base) to electron deficient atomic centers (Lewis acids),
and as an acceptor of hydrogen bonding.

To see an inversion of Ammonia, please click on the image above.
Other hybridizations of nitrogen such as sp2 and sp are also possible (see examples of compounds below).
The electronic structure of atomic oxygen is:1s2 2s2 2px2 2py 2pz. Mixing of the two 2p orbitals and 2s orbital gives four sp3 hybridized orbitals, of which two are half-filled and available for bonding. Each of the two remaining orbitals feature two electrons not available for bonding (nonbonding). The valency of oxygen is therefore 2, and the valence angle is close to that of tetrahedral.
Similarly to the carbon- and nitrogen-containing molecules the
sp2 hybridization is also possible. In this case only one of the
sp2 orbitals is half-filled and can form a
bond. The remaining orbitals are: two
sp2 orbitals fully filled and oriented in-plane with the
-bond (nonbonding), and one 2p orbital
available for
-bonding. This situation is
realized in the carbonyl group. The sp hybridization is normally not
encountered in oxygen compounds.